document.write( "Question 408715: sin(a+b)-sin(a-b)=2cosasinb
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document.write( "How do I solve this problem? I am so close to a break down over this. Help!!
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Algebra.Com's Answer #287850 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! sin(a+b)-sin(a-b)=2cos(a)sin(b)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin(a)cos(b)+cos(a)sin(b)-(sin(a)cos(b)-cos(a)sin(b))=2cos(a)sin(b)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin(a)cos(b)+cos(a)sin(b)-sin(a)cos(b)+cos(a)sin(b)=2cos(a)sin(b)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(sin(a)cos(b)-sin(a)cos(b))+(cos(a)sin(b)+cos(a)sin(b))=2cos(a)sin(b)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0+2cos(a)sin(b)=2cos(a)sin(b)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2cos(a)sin(b)=2cos(a)sin(b)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the original equation is an identity (ie it's true for ALL values of 'a' and 'b')\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jim \n" ); document.write( " |