document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408707>Question 408707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Directions: Setting Up and Solving an Algebraic Equations\r<BR>\n" );
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document.write( "One of the angles of a triangle has a measure of 40degrees. Find the measures of the other two angles if the difference between their measures is 10 degrees.\r<BR>\n" );
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document.write( "My work<BR>\n" );
document.write( "c=angles<BR>\n" );
document.write( "2c-10=40<BR>\n" );
document.write( "2c=50<BR>\n" );
document.write( "c=25<BR>\n" );
document.write( "Help please!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287828 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287828\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Not quite. If c and c-10 are the angles, then their sum must be 140, not 40.\r<BR>\n" );
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document.write( "2c - 10 = 140\r<BR>\n" );
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document.write( "2c = 150 --> c = 75, so the other two angles are 75 and 65 (degrees). </SPAN>\n" );
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