document.write( "Question 408682: Solve the following exponential equations using logarithms:\r
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document.write( "2^(x) = 3^(x+1)\r
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document.write( "Feeling pretty lost on this one...
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document.write( "I've tried to google for similar examples, but when I do find a similar problem it's solves using a form like this: \"xln(2)=(xln(3)+ln(3))\" I think this is a little beyond where I am now :( Looking for a more basic algebra solution! \r
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document.write( "Appreciate any help!!
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document.write( "Thanks :) \n" );
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Algebra.Com's Answer #287822 by richard1234(7193) You can put this solution on YOUR website! The ln function shouldn't be too far beyond your reach, since ln is a logarithm function (except it uses the base \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The easiest way to solve this is to isolate the 1 on the exponent x+1 to obtain\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the log base 2/3 of both sides to obtain\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |