document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408571>Question 408571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation for x and show your work. -2x + 51 = -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287791 by </B><A HREF=/tutors/aboutme.mpl?userid=clarkp><B>clarkp(14)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=clarkp><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=clarkp><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> HELLO:::\r<BR>\n" );
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document.write( "GIVEN<BR>\n" );
document.write( " -2x+51 =-3 --- using the addition property of equality<BR>\n" );
document.write( " -2x + 51 -51 =-3-51 <BR>\n" );
document.write( " -2x=-54<BR>\n" );
document.write( "  using the inverse property of multiplication<BR>\n" );
document.write( "  -2x(1/2) = -54(1/2)<BR>\n" );
document.write( " therefore x= -27\r<BR>\n" );
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document.write( "CHEER!!!! it's me, CLARK APPROACHABLE ONE WILLING TO HELP\r<BR>\n" );
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