document.write( "Question 408521: The length of a rectangle is 2 meters more than its width. If the area is 35 square meters, what are the length and width?
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Algebra.Com's Answer #287772 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "length of a rectangle is 2 meters more than its width.
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document.write( "Let x and (x+2) represent the width and length respectively
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document.write( "Question states***
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document.write( "x(x+2) = 35 m^2
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document.write( "Solving for x
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document.write( " x^2 + 2x - 35 = 0
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document.write( "factoring
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document.write( "(x+7)(x-5)= 0 Note:SUM of the inner product(7x) and the outer product(-5x) = 2x
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document.write( " (x+7)=0  |tossing out negative solution for length
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document.write( " (x-5)= 0  x = 5m, the width.  The length is 7m.  (5m + 2m)
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document.write( "CHECKING our Answer***
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document.write( "  5m*7m = 35 m^2 \n" );
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