document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408497>Question 408497</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A runner's best time for the mile was:<BR>\n" );
document.write( "4 min 53 sec in 2004<BR>\n" );
document.write( "4 min 38 sec in 2005<BR>\n" );
document.write( "4 min 20 sec in 2006<BR>\n" );
document.write( "find the average rate of change in seconds per year.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287764 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lets change every year time to seconds so: 4*60 + 53 = 293 sec and we have<BR>\n" );
document.write( "293 sec in 2004<BR>\n" );
document.write( "278 sec in 2005<BR>\n" );
document.write( "260 sec in 2006<BR>\n" );
document.write( "So in 2005 the rate of change in seconds as a DECREASE of 278/293 = 94%.<BR>\n" );
document.write( "In 2006 the rate of change in seconds as a DECREASE of 260/278 = 93%.<BR>\n" );
document.write( "We would get the average rate of change as a DECREASE of (94%+93%)/2 = 93.5%.\r<BR>\n" );
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