document.write( "Question 408464: solve using a system of equations.\r
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document.write( "I know you have to do something like x+y+x+y=, but then I get so confused.\r
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document.write( "A 40% saline solution is to be mixed with a 60% saline solution to obtain 8 liters of a 55% solution. How many liters of each solution should be used? \n" );
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Algebra.Com's Answer #287752 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! In words: \n" ); document.write( "(liters of salt in 40% solution + liters of salt in 60% solution)/(liters of solution) = 55% \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( "--------------------------------- \n" ); document.write( "given: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------ \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "This is 2 equations and 2 unknowns, so it's solvable \n" ); document.write( "---------------------- \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and, also, \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "Subtract (2) from (1) \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and, since \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( "2 liters of 40% solution and 6 liters of 60% solution are needed \n" ); document.write( "check answer: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |