document.write( "Question 408347: To train for a marathon, Mei runs an 18-mile course at constant speed. If she doubles her usual speed, she can compete the course in an hour and a half less than her usual time. What is Mei's usual speed and her usual time to compete the course \n" ); document.write( "
Algebra.Com's Answer #287741 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mei runs an 18-mile course at constant speed. \n" ); document.write( " If she doubles her usual speed, she can compete the course in an hour and a half less than her usual time. \n" ); document.write( "What is Mei's usual speed and her usual time to compete the course? \n" ); document.write( ": \n" ); document.write( "Change 1 hr and a half to 1.5 hrs \n" ); document.write( ": \n" ); document.write( "Let s = the normal speed \n" ); document.write( "then \n" ); document.write( "2s = double the normal speed \n" ); document.write( ": \n" ); document.write( "Write a time equation, Time = dist/speed \n" ); document.write( ": \n" ); document.write( "Usual time - faster time = 1.5 hrs \n" ); document.write( " \n" ); document.write( "multiply by 2s to clear denominators, results: \n" ); document.write( "2(18) - 18 = 2s(1.5) \n" ); document.write( "36 - 18 = 3s \n" ); document.write( "18 = 3s \n" ); document.write( "s = \n" ); document.write( "s = 6 mph is the usual speed \n" ); document.write( ": \n" ); document.write( "Find the usual time \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the time at the faster speed (12 mph) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |