document.write( "Question 408347: To train for a marathon, Mei runs an 18-mile course at constant speed. If she doubles her usual speed, she can compete the course in an hour and a half less than her usual time. What is Mei's usual speed and her usual time to compete the course \n" ); document.write( "
Algebra.Com's Answer #287741 by ankor@dixie-net.com(22740)\"\" \"About 
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Mei runs an 18-mile course at constant speed.
\n" ); document.write( " If she doubles her usual speed, she can compete the course in an hour and a half less than her usual time.
\n" ); document.write( "What is Mei's usual speed and her usual time to compete the course?
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\n" ); document.write( "Change 1 hr and a half to 1.5 hrs
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\n" ); document.write( "Let s = the normal speed
\n" ); document.write( "then
\n" ); document.write( "2s = double the normal speed
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\n" ); document.write( "Write a time equation, Time = dist/speed
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\n" ); document.write( "Usual time - faster time = 1.5 hrs
\n" ); document.write( "\"18%2Fs\" - \"18%2F%282s%29\" = 1.5
\n" ); document.write( "multiply by 2s to clear denominators, results:
\n" ); document.write( "2(18) - 18 = 2s(1.5)
\n" ); document.write( "36 - 18 = 3s
\n" ); document.write( "18 = 3s
\n" ); document.write( "s = \"18%2F3\"
\n" ); document.write( "s = 6 mph is the usual speed
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\n" ); document.write( "Find the usual time
\n" ); document.write( "\"18%2F3\" = 3 hrs is the usual time
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\n" ); document.write( "Check solution by finding the time at the faster speed (12 mph)
\n" ); document.write( "\"18%2F12\" = 1.5 hrs, which is 1.5 hrs faster than the usual time of 3 hrs
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