document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408363>Question 408363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 2:00pm a runner heads north on a highway, jogging at 10mph. At 2:30pm a driver heads north on the same highway to pick up the runner. If the car travels at 55mph, how long will it take the driver to catch the runner? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287713 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287713\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 2:00pm a runner heads north on a highway, jogging at 10mph. At 2:30pm a driver heads north on the same highway to pick up the runner. If the car travels at 55mph, how long will it take the driver to catch the runner?<BR>\n" );
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document.write( "Both runner and driver covered the same distance.<BR>\n" );
document.write( "Let x=hours driver will catch up with runner.<BR>\n" );
document.write( "Then 55x=distance driver covered<BR>\n" );
document.write( "Runner ran for 1/2 hour plus the catch up time.<BR>\n" );
document.write( "Then 10((1/2)+x)=distance runner covered.<BR>\n" );
document.write( "10((1/2)+x)=55x<BR>\n" );
document.write( "5+10x=55x<BR>\n" );
document.write( "45x=5<BR>\n" );
document.write( "x=1/9 hr<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "I would take the driver 1/9 hour to catch up with the runner. </SPAN>\n" );
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