document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408266>Question 408266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am needing some help Please. <BR>\n" );
document.write( "In solving the equation (x + 3)(x + 1) = 48, Eric stated that the solution would be<BR>\n" );
document.write( "x + 3 = 48 => x = 45<BR>\n" );
document.write( "or<BR>\n" );
document.write( "(x + 1) = 48 => x = 47<BR>\n" );
document.write( "However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning. Please show all work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287704 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287704\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I don't know where you get these problems from, but I solved a very similar problem yesterday (involving the same step, including a person named Eric. Different coefficients, though). Here's a link to the solution I posted:\r<BR>\n" );
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document.write( "http://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/Polynomials-and-rational-expressions.faq.question.407321.html\r<BR>\n" );
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document.write( "I don't think that Eric knows the \"zero property rule\" cannot be applied in a similar manner to other numbers :) </SPAN>\n" );
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