document.write( "Question 408306: solve the equation by completing the square\r
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Algebra.Com's Answer #287700 by richard1234(7193) $\"\"$ $\"About$

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1. For the quadratic $\"x%5E2+-+12x+=+5\"$ , add $\"36\"$ to both sides to obtain\r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2+-+12x+%2B+36+=+41\"$ Factor:\r
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\n" ); document.write( "\n" ); document.write( " $\"%28x-6%29%5E2+=+41\"$ --> $\"x-6+=+sqrt%2841%29\"$ or $\"x-6+=+-sqrt%2841%29\"$ . From here it follows that $\"x+=+6+%2B-+sqrt%2841%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "2. The equation $\"%28x-3%29%5E2+=+36\"$ does not need any square completion, we can simply take the square root of both sides (note that the negative square root can still count) to get $\"x-3+=+6\"$ , $\"x-3+=+-6\"$ --> $\"x+=+9\"$ or $\"x+=+-3\"$ .\r
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