document.write( "Question 408261: hi i need help with quadratic equations and i need steps please
\n" ); document.write( "1)(x-6)(x-4)=0
\n" ); document.write( "2)(x+2)(x-2)=0
\n" ); document.write( "3)(x+6)(x+3)=0
\n" ); document.write( "4)(x-4)(x+7)+0
\n" ); document.write( "5)x(-7)=0
\n" ); document.write( "6)(x-5)(x-2)=0
\n" ); document.write( "7)(x-8)(x-6)=0
\n" ); document.write( "8)(x+4)(x-4)=0
\n" ); document.write( "9)x(x+5)=0
\n" ); document.write( "10)(x-1)(x-8=0
\n" ); document.write( "11)(x-2)(2x-1)=0
\n" ); document.write( "12)(3x-2)(x+3)=
\n" ); document.write( "13)(x+5)(4x-1)=0
\n" ); document.write( "14)(2x-1)(3x+1)=0
\n" ); document.write( "15)4x(2x-3)=0\r
\n" ); document.write( "\n" ); document.write( "i need steps to please
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Algebra.Com's Answer #287675 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "1)(x-6)(x-4)=0\r
\n" ); document.write( "\n" ); document.write( "the first one inside the brackets (x-6)=0 , and the second one inside the brackets (x-4)=0; the first one equals x=6, the second one equals x=4\r
\n" ); document.write( "\n" ); document.write( "2)(x+2)(x-2)=0
\n" ); document.write( "the first one inside the brackets (x+2)=0 , and the second one inside the brackets (x-2)=0; the first one equals x=-2, the second one equals x=2\r
\n" ); document.write( "\n" ); document.write( "3)(x+6)(x+3)=0\r
\n" ); document.write( "\n" ); document.write( "the first one inside the brackets (x+6)=0 , and the second one inside the brackets (x+3)=0; the first one equals x=-6, the second one equals x=-3\r
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\n" ); document.write( "\n" ); document.write( "4)(x-4)(x+7)=0
\n" ); document.write( "the first one inside the brackets (x-4)=0 and the second one inside the brackets
\n" ); document.write( "(x+3)=0; the first one equals x=4, the second one equals x=-3\r
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\n" ); document.write( "\n" ); document.write( "5)x(-7)=0\r
\n" ); document.write( "\n" ); document.write( "since (-7) is not equal to zero, then x must be zero; x=0\r
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\n" ); document.write( "\n" ); document.write( "6)(x-5)(x-2)=0
\n" ); document.write( "the first one inside the brackets (x-5)=0 and the second one inside the brackets
\n" ); document.write( "(x-2)=0; the first one equals x=5, the second one equals x=2\r
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\n" ); document.write( "\n" ); document.write( "7)(x-8)(x-6)=0
\n" ); document.write( "the first one inside the brackets (x-8)=0 and the second one inside the brackets
\n" ); document.write( "(x-6)=0; the first one equals x=8, the second one equals x=6\r
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\n" ); document.write( "\n" ); document.write( "8)(x+4)(x-4)=0
\n" ); document.write( "the first one inside the brackets (x+4)=0 and the second one inside the brackets
\n" ); document.write( "(x-4)=0; the first one equals x=-4, the second one equals x=4\r
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\n" ); document.write( "\n" ); document.write( "9)x(x+5)=0
\n" ); document.write( "the first one x=0, second one (x+5)=0; therefore second one x=-5\r
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\n" ); document.write( "\n" ); document.write( "10)(x-1)(x-8=0\r
\n" ); document.write( "\n" ); document.write( "the first one inside the brackets (x-1)=0 and the second one inside the brackets
\n" ); document.write( "(x-8)=0; the first one equals x=1, the second one equals x=8\r
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\n" ); document.write( "\n" ); document.write( "11)(x-2)(2x-1)=0
\n" ); document.write( "the first one inside the brackets (x-2)=0 and the second one inside the brackets
\n" ); document.write( "(2x-1)=0; the first one equals x=2, the second one equals 2x=1..therefore x=1/2\r
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\n" ); document.write( "\n" ); document.write( "12)(3x-2)(x+3)=0\r
\n" ); document.write( "\n" ); document.write( "the first one inside the brackets (3x-2)=0 and the second one inside the brackets
\n" ); document.write( "(x+3)=0; the first one equals 3x=2...or x=2/3, the second one equals x=-3\r
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\n" ); document.write( "\n" ); document.write( "13)(x+5)(4x-1)=0\r
\n" ); document.write( "\n" ); document.write( "the first one inside the brackets (x+5)=0 and the second one inside the brackets
\n" ); document.write( "(4x-1)=0; the first one equals x=-5, the second one equals 4x=1..therefore x=1/4\r
\n" ); document.write( "\n" ); document.write( "14)(2x-1)(3x+1)=0\r
\n" ); document.write( "\n" ); document.write( "the first one inside the brackets (2x-1)=0 and the second one inside the brackets
\n" ); document.write( "(3x+1)=0; the first one equals 2x=1 or x=1/2, the second one equals 3x=-1..therefore x=-1/3\r
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\n" ); document.write( "\n" ); document.write( "15)4x(2x-3)=0\r
\n" ); document.write( "\n" ); document.write( "the first one 4x=0 only if x=0\r
\n" ); document.write( "\n" ); document.write( "the second one inside the brackets
\n" ); document.write( "(2x-3)=0;......2x=3 or x=3/2\r
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