document.write( "Question 408278: I am having a lot of difficulty with this problem.\r
\n" ); document.write( "\n" ); document.write( "I hope the modified square root symbol is clear. The square root symbol is covering the 2x + 7.\r
\n" ); document.write( "\n" ); document.write( "Solve the equation:
\n" ); document.write( " _____
\n" ); document.write( "√2x + 7 - (x + 2) = 0
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Algebra.Com's Answer #287673 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
√(2x + 7) - (x + 2) = 0
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\n" ); document.write( "sqrt(2x+7) = (x+2)
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "2x+7 = x^2+4x+4
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\n" ); document.write( "Modify:
\n" ); document.write( "x^2 + 2x - 3 = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "(x+3)(x-1) = 0
\n" ); document.write( "---
\n" ); document.write( "Possible answers: x = -3 or x = 1
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\n" ); document.write( "Checking the possible answers in the original equation:
\n" ); document.write( "sqrt(2x+7) = (x+2)\r
\n" ); document.write( "\n" ); document.write( "x= -3 ???
\n" ); document.write( "sqrt(2(-3)+7) =(-3+2)
\n" ); document.write( "sqrt(1) = -1
\n" ); document.write( "No
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\n" ); document.write( "x = 1 ???
\n" ); document.write( "sqrt(2x+7) = (x+2)
\n" ); document.write( "sqrt(2(1)+7) = (1+2)
\n" ); document.write( "sqrt(9) = 3
\n" ); document.write( "3 = 3
\n" ); document.write( "Yes
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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