document.write( "Question 408278: I am having a lot of difficulty with this problem.\r
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document.write( "I hope the modified square root symbol is clear. The square root symbol is covering the 2x + 7.\r
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document.write( "Solve the equation:
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document.write( "√2x + 7 - (x + 2) = 0 \n" );
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Algebra.Com's Answer #287673 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! √(2x + 7) - (x + 2) = 0 \n" ); document.write( "---- \n" ); document.write( "sqrt(2x+7) = (x+2) \n" ); document.write( "Square both sides to get: \n" ); document.write( "2x+7 = x^2+4x+4 \n" ); document.write( "--- \n" ); document.write( "Modify: \n" ); document.write( "x^2 + 2x - 3 = 0 \n" ); document.write( "--- \n" ); document.write( "Factor: \n" ); document.write( "(x+3)(x-1) = 0 \n" ); document.write( "--- \n" ); document.write( "Possible answers: x = -3 or x = 1 \n" ); document.write( "--- \n" ); document.write( "Checking the possible answers in the original equation: \n" ); document.write( "sqrt(2x+7) = (x+2)\r \n" ); document.write( "\n" ); document.write( "x= -3 ??? \n" ); document.write( "sqrt(2(-3)+7) =(-3+2) \n" ); document.write( "sqrt(1) = -1 \n" ); document.write( "No \n" ); document.write( "---------------- \n" ); document.write( "x = 1 ??? \n" ); document.write( "sqrt(2x+7) = (x+2) \n" ); document.write( "sqrt(2(1)+7) = (1+2) \n" ); document.write( "sqrt(9) = 3 \n" ); document.write( "3 = 3 \n" ); document.write( "Yes \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " \n" ); document.write( " |