document.write( "Question 408222: use the vertex formula to find the vertex
\n" ); document.write( "find the intervals where f is increasing and where f is decreasing\r
\n" ); document.write( "\n" ); document.write( "f(x)=2x^2-4x+1
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Algebra.Com's Answer #287660 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29=2x%5E2-4x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "The vertex is found using the formula for (x,y):\r
\n" ); document.write( "\n" ); document.write( "(-b/2a,f(-b/2a))\r
\n" ); document.write( "\n" ); document.write( "find \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-b%2F2a=-%28-4%29%2F2%2A2=4%2F4=1\"...so we have (1,y)..now find \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=f%28-b%2F2a%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%281%29=2%2A1%5E2-4%2A1%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"f%281%29=2-4%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"f%281%29=-1\"................ so the vertex is (1,-1)\r
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\n" ); document.write( "\n" ); document.write( "the intervals on which the function is increasing and the intervals on which the function is decreasing\r
\n" ); document.write( "\n" ); document.write( "Given the vertex of (1,-1):\r
\n" ); document.write( "\n" ); document.write( "The function is decreasing on:\r
\n" ); document.write( "\n" ); document.write( "(-∞,1)\r
\n" ); document.write( "\n" ); document.write( "The function is increasing on:\r
\n" ); document.write( "\n" ); document.write( "(1,∞)\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+2x%5E2-4x%2B1%29+\"\r
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