document.write( "Question 408140: Eva invested a certain amount of money at 8% interest and $1500 more than that amount at 12%. Her total yearly interest was $815. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #287655 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .08X+.12(X+1,500)=815 \n" ); document.write( ".08X+.12X+180=815 \n" ); document.write( ".20X=0=815-180 \n" ); document.write( ".20X=635 \n" ); document.write( "X=635/.20 \n" ); document.write( "X=3,175 IS THE AMOUNT INVESTED @ 8% \n" ); document.write( "3,175+1,500=4,675 IS THE AMOUNT INVESTED @ 10%. \n" ); document.write( "PROOF: \n" ); document.write( ".08*3,175+.12*4,675=815 \n" ); document.write( "254+561=815 \n" ); document.write( "815=815 \n" ); document.write( " |