document.write( "Question 408140: Eva invested a certain amount of money at 8% interest and $1500 more than that amount at 12%. Her total yearly interest was $815. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #287655 by checkley79(3341)\"\" \"About 
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.08X+.12(X+1,500)=815
\n" ); document.write( ".08X+.12X+180=815
\n" ); document.write( ".20X=0=815-180
\n" ); document.write( ".20X=635
\n" ); document.write( "X=635/.20
\n" ); document.write( "X=3,175 IS THE AMOUNT INVESTED @ 8%
\n" ); document.write( "3,175+1,500=4,675 IS THE AMOUNT INVESTED @ 10%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*3,175+.12*4,675=815
\n" ); document.write( "254+561=815
\n" ); document.write( "815=815
\n" ); document.write( "
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