document.write( "Question 408207: Cant seem to get started on this one. Quadriatic in the unknown.\r
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Algebra.Com's Answer #287640 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "6/x^2+1/x-2=0    (Substitute u=1/x)
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document.write( "6u^2 + u - 2 = 0
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document.write( "factoring
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document.write( "(3u+2 )(2u-1)=0 Note:SUM of the inner product(4u) and the outer product(-3u) = u
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document.write( "  (3u+2 )=0  u = -2/3    1/x = -2/3    x = -3/2
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document.write( "  (2u-1)=0   u = 1/2     1/x = 1/2     x = 2\r
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document.write( "CHECKING our Answer***
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document.write( "6/x^2+1/x-2=0 OR
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document.write( "6 + x - 2x^2 = 0
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document.write( "6 - 3/2 - 18/4 = 0
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document.write( "6 + 2 - 8 = 0 \n" );
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