document.write( "Question 408193: The mean of a normal probability distribution is 87 and the standard deviation is 4. What is the probability of a value greater than 90?
\n" ); document.write( "A) .2734
\n" ); document.write( "B) .7734
\n" ); document.write( "C) .2420
\n" ); document.write( "D) .2264
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Algebra.Com's Answer #287634 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "mean of a normal probability distribution is 87 and the standard deviation is 4. 
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document.write( "*Note: 
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document.write( "  z = (90-87)/4 = 3/4 = .75  |NORMSDIST(0.75) = .77337
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document.write( " P(z > .75) = 1 - .77337 = .25335 \n" );
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