document.write( "Question 408154: a new schedule for a train requires it to go 270 miles in 26 minutes less time than before. To do thsi it must average 4 mpoh faster. What must its new average speed be? \n" ); document.write( "
Algebra.Com's Answer #287618 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! a new schedule for a train requires it to go 270 miles in 26 minutes less time than before. \n" ); document.write( " To do this it must average 4 mph faster. \n" ); document.write( " What must its new average speed be? \n" ); document.write( ": \n" ); document.write( "Let s = the new average speed \n" ); document.write( "then \n" ); document.write( "(s-4) = the old average speed \n" ); document.write( ": \n" ); document.write( "Change 26 min to \n" ); document.write( ": \n" ); document.write( "write a time equation: time = dist/speed \n" ); document.write( "Old time - new time = 26 min \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by 30s(s-4) to get rid of the denominators, results: \n" ); document.write( "30s(270) - 30(s-4)(270) = 13s(s-4) \n" ); document.write( "8100s - 8100(s-4) = 13s^2 - 52s \n" ); document.write( "8100s - 8100s + 32400 = 13s^2 - 52s \n" ); document.write( "Combine to form a quadratic equation \n" ); document.write( "0 = 13s^2 - 52s - 32400 \n" ); document.write( "Solve this using the quadratic formula a=13, b=-52, c=-32400 \n" ); document.write( ": \n" ); document.write( "The positive solution: s = 51.963 ~ 52 mph is the new average speed \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution in decimals \n" ); document.write( "270/48 - 270/52 = .4327 * 60 ~ 26.0 min \n" ); document.write( " |