document.write( "Question 408154: a new schedule for a train requires it to go 270 miles in 26 minutes less time than before. To do thsi it must average 4 mpoh faster. What must its new average speed be? \n" ); document.write( "
Algebra.Com's Answer #287618 by ankor@dixie-net.com(22740)\"\" \"About 
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a new schedule for a train requires it to go 270 miles in 26 minutes less time than before.
\n" ); document.write( " To do this it must average 4 mph faster.
\n" ); document.write( " What must its new average speed be?
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\n" ); document.write( "Let s = the new average speed
\n" ); document.write( "then
\n" ); document.write( "(s-4) = the old average speed
\n" ); document.write( ":
\n" ); document.write( "Change 26 min to \"26%2F60\" = \"13%2F30\" hrs
\n" ); document.write( ":
\n" ); document.write( "write a time equation: time = dist/speed
\n" ); document.write( "Old time - new time = 26 min
\n" ); document.write( "\"270%2F%28s-4%29\" - \"270%2Fs\" = \"13%2F30\"
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 30s(s-4) to get rid of the denominators, results:
\n" ); document.write( "30s(270) - 30(s-4)(270) = 13s(s-4)
\n" ); document.write( "8100s - 8100(s-4) = 13s^2 - 52s
\n" ); document.write( "8100s - 8100s + 32400 = 13s^2 - 52s
\n" ); document.write( "Combine to form a quadratic equation
\n" ); document.write( "0 = 13s^2 - 52s - 32400
\n" ); document.write( "Solve this using the quadratic formula a=13, b=-52, c=-32400
\n" ); document.write( ":
\n" ); document.write( "The positive solution: s = 51.963 ~ 52 mph is the new average speed
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\n" ); document.write( ":
\n" ); document.write( "Check solution in decimals
\n" ); document.write( "270/48 - 270/52 = .4327 * 60 ~ 26.0 min
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