document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408157>Question 408157</A>: <I><SPAN STYLE=\"word-break: break-all;\"> angle A and angle B are complimentary. if angle a is 6 more that 3 times angle b what is each angle. solve in 5 steps </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287610 by </B><A HREF=/tutors/aboutme.mpl?userid=katealdridge><B>katealdridge(100)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=katealdridge><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=katealdridge><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A+B=90. A=3B + 6<BR>\n" );
document.write( "Substitute 3B+6 for A in the first equation.<BR>\n" );
document.write( "3B+6+B=90 combine like terms<BR>\n" );
document.write( "4B+6=90 subtract 6 from both sides<BR>\n" );
document.write( "4B=84 divide both sides by 4<BR>\n" );
document.write( "B=21<BR>\n" );
document.write( "A=90-21=69. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );