document.write( "Question 408138: A 40% saline solution is to be mixed with a 60% saline solution to obtain 8 liters of a 55% saline solution. How many liters of each solution should be used? \n" ); document.write( "

Algebra.Com's Answer #287595 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x and (8L-x)represent the amounts of the 60% and 40% solutions respectively
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document.write( "Question states***
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document.write( " .60x + .40(8L-x) = .55*8L
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document.write( "Solving for x
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document.write( "       .20x =  .15*8L  x = 6L, amount of 60%,  2L of 40%.  (8L-6L)
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document.write( "CHECKING our Answer***
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document.write( "  .6*6 + .4*2 = 4.4 = .55*8 \n" );
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