document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408109>Question 408109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is 4 times as large as the first. The third angle is 110 more than the sum of the other two angles. Find the measure of the second angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287573 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is 4 times as large as the first. The third angle is 110 more than the sum of the other two angles. Find the measure of the second angle.<BR>\n" );
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document.write( "Let x = first angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "4x = second angle<BR>\n" );
document.write( "x+4x+110 = third angle<BR>\n" );
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document.write( "x + 4x + x+4x+110 = 180<BR>\n" );
document.write( "10x+110 = 180<BR>\n" );
document.write( "10x = 70<BR>\n" );
document.write( "x = 7 degrees<BR>\n" );
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document.write( "Second angle:<BR>\n" );
document.write( "4x = 4(7) = 28 degrees </SPAN>\n" );
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