document.write( "Question 408112: the perimeter of a rectangle 240. The lenght exceeds the width by 40 inches. find the lenght and width \n" ); document.write( "

Algebra.Com's Answer #287570 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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If the width of the rectangle is x inches, then lengthis $\"%28x%2B40%29\"$ inches
\n" ); document.write( "The perimeter of rectangle is $\"P=2%2A%28W%2BL%29\"$ , when W - width, L - length
\n" ); document.write( "so perimeter is $\"2%2A%28x%2Bx%2B40%29=2%2A%282x%2B40%29\"$
\n" ); document.write( "Equation
\n" ); document.write( " $\"2%2A%282x%2B40%29=240\"$ devide by 2
\n" ); document.write( " $\"2x%2B40=120\"$
\n" ); document.write( " $\"2x=120-40\"$
\n" ); document.write( " $\"2x=80\"$
\n" ); document.write( " $\"x=80%2F2\"$
\n" ); document.write( " $\"x=40\"$
\n" ); document.write( "so the width is 40 inches, then the length is 40+40=80 inches \n" ); document.write( "

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