document.write( "Question 405072: put in standard form, state the type of graph it will produce, and center,key point, and/or radius for the following:\r
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document.write( "X^2 + (y-2)^2=7\r
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document.write( "x^2+6x+4y^2+8y=-13 ( for this one i know one must complete the square, but the 4
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document.write( " in front of the y throws me off on the equation into standard form) \r
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document.write( "xy=7 ( im pretty sure that this equation doesn't make a graph, but im not confident about my answer on noting)\r
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Algebra.Com's Answer #287548 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! put in standard form, state the type of graph it will produce, and center,key point, and/or radius for the following: \n" ); document.write( "X^2 + (y-2)^2=7 \n" ); document.write( "x^2+6x+4y^2+8y=-13 ( for this one i know one must complete the square, but the 4 \n" ); document.write( "in front of the y throws me off on the equation into standard form) \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "x^2+(y-2)^2=7 \n" ); document.write( "This is a circle with center at (0,2) with radius=sqrt(7) \n" ); document.write( "Standard form for circle:(x-h)^2+(y-k)^2=r^2. \n" ); document.write( "In this case, h=0,k=2, and r^2=7 \n" ); document.write( ".. \n" ); document.write( "x^2+6x+4y^2+8y=-13 \n" ); document.write( "complete the square \n" ); document.write( "(x^2+6x+9)+4(y^2+2y+1)=-13+9+4=0 \n" ); document.write( "(x+3)^2+4(y+1)^2=0 \n" ); document.write( "This does not fit into any of the equations for conics that I know of. Maybe there is a typing error here. If you try to solve it for y, you will get imaginary solutions.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |