document.write( "Question 407622: (2-5i)(6+7i)
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Algebra.Com's Answer #287542 by jsmallt9(3758) $\"\"$ $\"About$

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(2-5i)(6+7i)
\n" ); document.write( "To multiply we just use FOIL. But first I like to change any subtractions into additions:
\n" ); document.write( "(2+(-5i))(6+7i)
\n" ); document.write( "Now we'll multiply:
\n" ); document.write( "2*6+2*7i+(-5i)*6+(-5i)*7i
\n" ); document.write( "which simplifies as follows:
\n" ); document.write( " $\"12%2B14i%2B%28-30i%29%2B%28-35i%5E2%29\"$
\n" ); document.write( "Since $\"i%5E2+=+-1\"$ :
\n" ); document.write( "12+14i+(-30i)+(-35)(-1)
\n" ); document.write( "12+14i+(-30i)+35
\n" ); document.write( "Adding like terms:
\n" ); document.write( "47+(-16i) \n" ); document.write( "

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