document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408055>Question 408055</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the digits of a three digit # are reversed, the new number is 198 less than the original #. If the hundreds digit is 3, and three less than the tens digit is 5* the units digit, what is the original #. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287519 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287519\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the hundred's digit is 3, and the tens digit is five times the units digit, the only possibilities are\r<BR>\n" );
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document.write( "300<BR>\n" );
document.write( "351, this works because 153 = 351 - 198. So our original number is 351. </SPAN>\n" );
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