document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408038>Question 408038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train leaves a train depot 2 hours after a freight train leaves the same depot. The freight train is traveling 20 mph slower than the passenger train. Find the rate of each train if the passenger train overtakes the freight train in 3 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287505 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> freight train = x mph<BR>\n" );
document.write( "passenger train = x+20 mph<BR>\n" );
document.write( "...<BR>\n" );
document.write( "freight train time = 3 +2 = 5 hours<BR>\n" );
document.write( "passanger train = 3 hours<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance same. because they meet<BR>\n" );
document.write( "..<BR>\n" );
document.write( "5x=3(x+20)<BR>\n" );
document.write( "5x=3x+60<BR>\n" );
document.write( "5x-3x=60<BR>\n" );
document.write( "2x= 60<BR>\n" );
document.write( "/2<BR>\n" );
document.write( "x= 30mph speed of freight train<BR>\n" );
document.write( "passenger train speed = 30+20 = 50mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );