document.write( "Question 407750: a girl has 30 coins consisting of nickels and dimes amounting to $2.60. how many coins of each kind does she have. \n" ); document.write( "
Algebra.Com's Answer #287481 by ankor@dixie-net.com(22740)\"\" \"About 
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a girl has 30 coins consisting of nickels and dimes amounting to $2.60.
\n" ); document.write( " how many coins of each kind does she have.
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\n" ); document.write( "Let n = no. of nickels
\n" ); document.write( "Let d = no. of dimes
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\n" ); document.write( "Write the no. of coins equation:
\n" ); document.write( "n + d = 30
\n" ); document.write( "n = (30-d); use this for substitution
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\n" ); document.write( "Write the total value equation
\n" ); document.write( ".05n + .10d = 2.60
\n" ); document.write( "replace n with (30-d)
\n" ); document.write( ".05(30-d) + .10d = 2.60
\n" ); document.write( "1.5 - .05d + .10d = 2.60
\n" ); document.write( "-.05d + .10d = 2.60 - 1.50
\n" ); document.write( ".05d = 1.10
\n" ); document.write( "d = \"1.10%2F.05\"
\n" ); document.write( "d = 22 dimes
\n" ); document.write( "then
\n" ); document.write( "30 - 22 = 8 nickels
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\n" ); document.write( "Check in the $ equation
\n" ); document.write( ".05(8) + .10(22) =
\n" ); document.write( ".40 + 2.20 = 2.60; confirms our solution
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