document.write( "Question 407974: \"1%2B+sqrt+%28x-3%29=9\"\r
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Algebra.Com's Answer #287457 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"1%2B+sqrt+%28x-3%29=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt+%28x-3%29=9+-1\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt+%28x-3%29=8\".........raise to the power of \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28sqrt+%28x-3%29%29%5E2=8%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=64\"\r
\n" ); document.write( "\n" ); document.write( "\"x=64%2B3\"\r
\n" ); document.write( "\n" ); document.write( "\"x=67\"\r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"1%2B+sqrt+%2867-3%29=9\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2B+sqrt+%2864%29=9\"\r
\n" ); document.write( "\n" ); document.write( "\"1%2B+8=9\"\r
\n" ); document.write( "\n" ); document.write( "\"9=9\"\r
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