document.write( "Question 407642: A printing company purchased a new copier that is twice as fast as the old copier. With both copiers working at the same time, it takes 10 hours to do a job. How long would it take the new copier working alone \n" ); document.write( "

Algebra.Com's Answer #287429 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A printing company purchased a new copier that is twice as fast as the old copier.
\n" ); document.write( " With both copiers working at the same time, it takes 10 hours to do a job.
\n" ); document.write( " How long would it take the new copier working alone
\n" ); document.write( ":
\n" ); document.write( "Let t = time required by the new copier working alone
\n" ); document.write( "then
\n" ); document.write( "2t = time required by the old copier alone
\n" ); document.write( ":
\n" ); document.write( "Let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "A typical shared work equation:
\n" ); document.write( ":
\n" ); document.write( " $\"10%2Ft\"$ + $\"10%2F%282t%29\"$ = 1
\n" ); document.write( "Multiply by 2t, results
\n" ); document.write( "2(10) + 10 = 2t
\n" ); document.write( "30 = 2t
\n" ); document.write( "t = $\"30%2F2\"$
\n" ); document.write( "t = 15 hrs the new copier working alone
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this:
\n" ); document.write( "10/15 + 10/30 =
\n" ); document.write( "2/3 + 1/3 = 1; confirms our solution of t = 15 \n" ); document.write( "

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