document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407760>Question 407760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I really need your help, math is not my greatest subject. I am in college physics and I would love it if you could please help. It is a very long question...here goes:<BR>\n" );
document.write( "A surveying team wishes to find the distance between a point (A) on one side of a sstream and a point (B) on the opposite bank. The surveyor sets thetransit over point A and backsights on point B. He then turns his transit through a 90 degree angle and foresights toward point C. The party sets point C at any convenient distance form A  using a steel tape measures a distance of 801 feet. The surveyor sets the transit over point C baxksights on A and turns the telescope towards point B. He maeasures the angle bewteen his sighting on A and his sighting on B and finds that it is 28 degrees with this information what is the distance from point A to point B?..........sorry it is so long..... I thank you very much for your help...god bless </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287423 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A surveying team wishes to find the distance between a point (A) on one side of a sstream and a point (B) on the opposite bank. The surveyor sets thetransit over point A and backsights on point B. He then turns his transit through a 90 degree angle and foresights toward point C. The party sets point C at any convenient distance form A using a steel tape measures a distance of 801 feet. The surveyor sets the transit over point C baxksights on A and turns the telescope towards point B. He maeasures the angle bewteen his sighting on A and his sighting on B and finds that it is 28 degrees with this information what is the distance from point A to point B?..<BR>\n" );
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document.write( "It helps to draw a right triangle representing this.<BR>\n" );
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document.write( "Show the stream between A and B, C is on the same side of the stream as A<BR>\n" );
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document.write( "Angle A is given as 90 degrees, Angle C is given as 28 degrees<BR>\n" );
document.write( "Side AC is given as 801 ft, we want to find side AB<BR>\n" );
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document.write( "We can use the tangent of C which is 28 degrees, Side adjacent = 801 ft<BR>\n" );
document.write( "we want to find x, side opposite, which is AB, the distance across the stream<BR>\n" );
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document.write( "Tan(28) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F801 ALIGN=MIDDLE  ALT=\"x%2F801\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".5317 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F801 ALIGN=MIDDLE  ALT=\"x%2F801\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Multiply both sides by 801, results<BR>\n" );
document.write( "801 * .5317 = x<BR>\n" );
document.write( "x = 425.9 ft is the distance across the stream (AB)<BR>\n" );
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document.write( "Did I explain in a manner that made sense to you?   </SPAN>\n" );
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