document.write( "Question 407816: Can someone please help, I am trying to help my child with algebra homework and I have no idea what I am doing on this problem. I do know A=L*W, but that is as far as I can remember with this stuff. Thank you.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 2 meters more than it's width. If the area is 63 sq meters, what are the length and width? \n" ); document.write( "
Algebra.Com's Answer #287377 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is 2 meters more than it's width. If the area is 63 sq meters, what are the length and width?
\n" ); document.write( "------
\n" ); document.write( "Let the width be \"x\"
\n" ); document.write( "Then the length is \"x+2\"
\n" ); document.write( "---
\n" ); document.write( "A = LW
\n" ); document.write( "63 = (x+2)x
\n" ); document.write( "63 = x^2+2x
\n" ); document.write( "x^2 +2x - 63 = 0
\n" ); document.write( "----
\n" ); document.write( "Factor:
\n" ); document.write( "(x+9)(x-7) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 7 meters (width)
\n" ); document.write( "---
\n" ); document.write( "x+2 = 9 meters (length)
\n" ); document.write( "============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "============== \n" ); document.write( "
\n" );