document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407741>Question 407741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> let f be a function with domain (-2,positive infinity) and range [-3,4].\r<BR>\n" );
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document.write( "Find the domain and range of y=-f(x+2)-3\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287356 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x+2) corresponds to a horizontal shift of the y-axis 2 units to the right, and so the new domain is (-4, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=infinity ALIGN=MIDDLE  ALT=\"infinity\"   DISABLED_style= \"max-width:90%; height:auto;\" >). <BR>\n" );
document.write( "-f(x+2)-2 implies reflection across the x-axis,  and then vertical shift of x-axis 3 units up, and so the new range is [3 - 3, -4 - 3], or [0, -7]. </SPAN>\n" );
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