document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407702>Question 407702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist leaves his training base for a morning workout, riding at the rate of 16 mph. One hour later, his support staff leaves the base in a car going 30 mph in the same direction. How long will it take the support staff to catch up with the cyclist once the car leaves the base? \r<BR>\n" );
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document.write( "I just wanna fid out how to set it up cause I  know the formula(r*t=d) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287332 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287332\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> t is the time to catch up<BR>\n" );
document.write( "the cyclist's time is t plus his one hr head start<BR>\n" );
document.write( "they catch up when the staff has traveled the same (equal) distance as the cyclist\r<BR>\n" );
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document.write( "16 * (t + 1) = 30 * (t) </SPAN>\n" );
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