document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407705>Question 407705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let(f)=ax^5+bx^3+cx+9 were a,b,and c are constants. <BR>\n" );
document.write( "If f(6)=17, determine the value of f(-6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287327 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note that all the x exponents (except for the 9) are odd, which means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E5+=+-%28-x%29%5E5 ALIGN=MIDDLE  ALT=\"x%5E5+=+-%28-x%29%5E5\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Since f(6) = 17, then f(6) - 9 = 8, and\r<BR>\n" );
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document.write( "Since the function is odd, then\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%2A%28-6%29%5E5+%2B+b%2A%28-6%29%5E3+%2B+c%2A%28-6%29+=+-8 ALIGN=MIDDLE  ALT=\"a%2A%28-6%29%5E5+%2B+b%2A%28-6%29%5E3+%2B+c%2A%28-6%29+=+-8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Adding 9 to obtain the value of f(-6) we get f(-6) = 1. </SPAN>\n" );
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