document.write( "Question 407524: (x^2+6x+9)/(x^2-9) what numbers are excluded \n" ); document.write( "

Algebra.Com's Answer #287287 by jim_thompson5910(35256) $\"\"$ $\"About$

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You CANNOT divide by zero. So this means that the denominator $\"x%5E2-9\"$ CANNOT be equal to zero. So if $\"x%5E2-9\"$ were zero, then $\"x%5E2-9=0\"$ and we'd find that $\"x=3\"$ or $\"x=-3\"$ .\r
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\n" ); document.write( "\n" ); document.write( "So if $\"x=3\"$ or $\"x=-3\"$ , then the denominator is zero. This is not allowed. So we must make the restrictions that x cannot equal 3 or x cannot equal -3.\r
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