document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407505>Question 407505</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The heating element is rated 1.80 kW when operating voltage is 0.24 kV. <BR>\n" );
document.write( "a)What is the current through it?<BR>\n" );
document.write( "b)What would its power consumption be if the potential difference drops to 0.12 kV?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287282 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The heating element is rated 1.80 kW when operating voltage is 0.24 kV. <BR>\n" );
document.write( "a)What is the current through it?<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "P = I*V<BR>\n" );
document.write( "1800 = I*240<BR>\n" );
document.write( "I = 1800/240 = 7.5 amps<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "b)What would its power consumption be if the potential difference drops to 0.12 kV?<BR>\n" );
document.write( "E = I*R<BR>\n" );
document.write( "R = E/I = 240/7.5 = 32 ohms<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "P = E^2/R<BR>\n" );
document.write( "@ 120 volts<BR>\n" );
document.write( "P = 120^2/32 = 450 watts </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );