document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407493>Question 407493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2(x-7)^1/3 +5 = 7<BR>\n" );
document.write( "(What would I need to do here?)\r<BR>\n" );
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document.write( "Also.. <BR>\n" );
document.write( "2x^1/2 +8 = 0\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287276 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To move the 5 from the left side of the equation to the right side of the equation add -5 to both sides of the equation<BR>\n" );
document.write( "2(x-7)^1/3 + 5 + -5 = 7-5<BR>\n" );
document.write( "2(x-7)^1/3 = 2<BR>\n" );
document.write( "(x-7)^1/3 = 1<BR>\n" );
document.write( "now we simply raise each side of the equation to the power 3 and get<BR>\n" );
document.write( "((x-7)^1/3)^3 = 1^3<BR>\n" );
document.write( "x-7 = 1<BR>\n" );
document.write( "x = 1+7<BR>\n" );
document.write( "x=8\r<BR>\n" );
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document.write( "to solve 2x^1/2 + 8 = 0 is similar. </SPAN>\n" );
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