document.write( "Question 407001: substitution method:
\n" ); document.write( "x=y-1
\n" ); document.write( "y=4-2x?
\n" ); document.write( "

Algebra.Com's Answer #287223 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "solving by substitution method:
\n" ); document.write( "x=y-1
\n" ); document.write( "y=4-2x\r
\n" ); document.write( "\n" ); document.write( "y = 4 - 2(y-1) |substituting for (y-1) for x
\n" ); document.write( " 3y = 6
\n" ); document.write( " y = 2 and x = 1 (2-1)\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " y = 4-2x
\n" ); document.write( " 2 = 4 - 2 \n" ); document.write( "
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