document.write( "Question 407329: I'm not sure I ma doing this right.
\n" ); document.write( "problem: (3/4)x*-1=1/2
\n" ); document.write( " I think i need to get the x by itself, so I would take the 3/4 and multiply it by 4/3, causing me to cancel it out. Leaving me with x-1=1/2. so then it's 1/1*1/2=1/2 so x=1/2? Is that right? I feel like I am missing something here.
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Algebra.Com's Answer #287216 by rfer(16322)\"\" \"About 
You can put this solution on YOUR website!
3/4x*-1=1/2
\n" ); document.write( "3/4x=1/2*-1/1
\n" ); document.write( "3/4x=-1/2
\n" ); document.write( "x=-1/2*4/3
\n" ); document.write( "x=-4/6
\n" ); document.write( "x=-2/3
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