document.write( "Question 407372: Canu help me correctly set up this problem...
\n" ); document.write( "How much of an alloy that is 30% copper should be mixed with 600oz of an alloy that is 90% copper in order to get an alloy that is 70% copper?
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Algebra.Com's Answer #287182 by katealdridge(100)\"\" \"About 
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Let # of ounces of 30% copper alloy = x
\n" ); document.write( "# of ounces of 90% copper alloy = 600.
\n" ); document.write( "\".30x%2B.90%28600%29=.70%28x%2B600%29\"
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