document.write( "Question 406810: Mr.Conley's present age is three times his daughter's present age. Five years ago, Mr.Conley was four times as old as his daughter was then. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #287173 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Mr.Conley's present age is three times his daughter's present age
\n" ); document.write( "Let x and 3x represent the daughter's and father's ages NOW respectively
\n" ); document.write( "Question states***
\n" ); document.write( "Five years ago, Mr.Conley was four times as old as his daughter was then
\n" ); document.write( " 3x - 5 = 4(x-5)
\n" ); document.write( "Solving for x
\n" ); document.write( " 3x - 5 = 4x - 20
\n" ); document.write( " 15 = x, the daughter's age NOW. Mr Conley is 45\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 40 = 4*10 \n" ); document.write( "
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