document.write( "Question 407300: graph the quadratic function f(x)=(x+3)^2+1 \n" ); document.write( "

Algebra.Com's Answer #287130 by graphmatics(170) $\"\"$ $\"About$

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Put y for f(x) and get
\n" ); document.write( "y = (x+3)^2 +1
\n" ); document.write( "y = x^2 + 6*x +9 +1
\n" ); document.write( "y = x^2 + 6*x + 10
\n" ); document.write( "we plot a group of quadratic equation (x,y) points for a group of x say {0, 1,-1,2,-2,3,-3}.
\n" ); document.write( "if x=0 then y = x^2 + 6*0 +10 so y=10 and (0,10) is a solution point for the quadratic equation y = x^2 + 6*x + 10.
\n" ); document.write( "For x=-3 y=3*2+6*3+10=17 and (-3,1) is a point and similarly for
\n" ); document.write( "x=-1,x=2,x=-2,x=3,x=-3
\n" ); document.write( " $\"+graph%28+500%2C+500%2C+-6%2C+5%2C+-10%2C+10%2C+0%2C+x%5E2%2B6%2Ax%2B10%29+\"$ \n" ); document.write( "

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