document.write( "Question 406783: The sum of the squares of three consecutive integers is 110. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #287113 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "three consecutive integers
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document.write( "Let x,(x+1),(x+2) represent the three consecutive integers
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document.write( "Question states***
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document.write( "x^2 +(x+1)^2+(x+2)^2 = 110
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document.write( "Solving for x
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document.write( " 3x^2 + 6x  + 5 = 110
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document.write( " 3x^2 + 6x  -105 = 0
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document.write( " 3(x^2 + 2x - 35)  = 0
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document.write( "  (x^2 + 2x - 35)  = 0 
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document.write( "factoring
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document.write( "  (x+7)(x-5) = 0 Note:SUM of the inner product(7x) and the outer product(-5x) = 2x
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document.write( "  (x+7)=0  |x = -7  The three consecutive integers are -5,-6,-7
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document.write( "  (x-5)=0  |x = 5   The three consecutive integers are 5,6,7\r
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document.write( "CHECKING our Answer(s)***
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document.write( "25 + 36 + 49 = 110 \n" );
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