document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407244>Question 407244</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 4x + 1 = 3x &#8722; 6, evaluate 5x &#8722; 6.\r<BR>\n" );
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document.write( "I just honestly do not understand how to work it. I have tried and tried and even used the help on my homework but I just don't understand how to work it. Please help me. I keep solving for x because that's all I know how to do.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287096 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x using:<BR>\n" );
document.write( "4x + 1 = 3x &#8722; 6<BR>\n" );
document.write( "x + 1 = &#8722;6<BR>\n" );
document.write( "x = -7<BR>\n" );
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document.write( "Then, using the above value of x, substitute it into:<BR>\n" );
document.write( "5x &#8722; 6<BR>\n" );
document.write( "5(-7) &#8722; 6<BR>\n" );
document.write( "-35 -6<BR>\n" );
document.write( "-41<BR>\n" );
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