document.write( "Question 407185: help me pleaseeeeeeeeeeeeee!\r
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document.write( "lemon drops are to be mixed with jelly beans to make 100 pounds of mixture.
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document.write( "refer to the illustration and compute how many pounds of each candy should be used.\r
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document.write( "lemon drops $1.90 lb.
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document.write( "jelly beans $1.20 lb.
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document.write( "mixture$1.48 lb. \n" );
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Algebra.Com's Answer #287053 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! lemon drops are to be mixed with jelly beans to make 100 pounds of mixture. \n" ); document.write( "refer to the illustration and compute how many pounds of each candy should be used. \n" ); document.write( "lemon drops $1.90 lb. \n" ); document.write( "jelly beans $1.20 lb. \n" ); document.write( "mixture$1.48 lb.\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "let x=lbs of lemon drops to use in mixture \n" ); document.write( "then 100-x=lbs jelly beans to use in mixture\r \n" ); document.write( "\n" ); document.write( "cost of lemon drops=1.9x \n" ); document.write( "cost of jelly beans=1.2(100-x) \n" ); document.write( "cost of the mixture=1.48*100\r \n" ); document.write( "\n" ); document.write( "cost of lemon drops and jelly beans=cost of mixture \n" ); document.write( "1.9x+1.2(100-x)=1.48*100 \n" ); document.write( "1.9x+120-1.2x=148 \n" ); document.write( ".7x=28 \n" ); document.write( "x=40lbs \n" ); document.write( "100-x=100-40=60lbs\r \n" ); document.write( "\n" ); document.write( "ans: \n" ); document.write( "pounds of lemon drops to use in mixture=40 \n" ); document.write( "pounds of jelly beans to use in mixture=60 \n" ); document.write( " |