document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=407125>Question 407125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the squares of three consecutive integers is 110. Find the numbers  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287044 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We could obtain a cubic, using the equation\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+%2B+%28x%2B1%29%5E2+%2B+%28x%2B2%29%5E2+=+110 ALIGN=MIDDLE  ALT=\"x%5E2+%2B+%28x%2B1%29%5E2+%2B+%28x%2B2%29%5E2+=+110\"   DISABLED_style= \"max-width:90%; height:auto;\" >. However, the problem implies that x is an integer, so the easiest way is probably to guess and check. We obtain x = 5 as our answer, as 25 + 36 + 49 = 110. However, x = -7 works as well, because <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%5E2+%2B+6%5E2+%2B+7%5E2+=+%28-7%29%5E2+%2B+%28-6%29%5E2+%2B+%28-5%29%5E2 ALIGN=MIDDLE  ALT=\"5%5E2+%2B+6%5E2+%2B+7%5E2+=+%28-7%29%5E2+%2B+%28-6%29%5E2+%2B+%28-5%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Therefore the integers are either {5, 6, 7} or {-7, -6, -5}. </SPAN>\n" );
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