document.write( "Question 407095: if a plane can travel 450 miles per hour with the wind and 410 miles per hour against the wind, find the speed of the plan in still air. \n" ); document.write( "

Algebra.Com's Answer #287032 by richard1234(7193) $\"\"$ $\"About$

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Let $\"R%5Bp%5D\"$ be the speed of the plane and $\"R%5Bw%5D\"$ be the speed of the wind. Then, the speed of the plane with the tail wind is given by\r
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\n" ); document.write( "\n" ); document.write( " $\"450+=+R%5Bp%5D+%2B+R%5Bw%5D\"$ , and the speed of the plane with the head wind is given by\r
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\n" ); document.write( "\n" ); document.write( " $\"410+=+R%5Bp%5D+%2B+R%5Bw%5D\"$ . Adding the two equations, we get\r
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\n" ); document.write( "\n" ); document.write( " $\"860+=+2R%5Bp%5D\"$ --> $\"R%5Bp%5D+=+430\"$ (mi/hr). \n" ); document.write( "

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