document.write( "Question 849: the base of a triangle is (2x+3) feet long and the height is (x+3) feet long. If the area of the triangle is 27 square feet, find the base and height of the triangle. \n" ); document.write( "

Algebra.Com's Answer #287 by prabhjyot(165) $\"\"$ $\"About$

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Area of the triangle =1/2 base* height
\n" ); document.write( "given base=(2x+3)
\n" ); document.write( "height=(x+3)
\n" ); document.write( "area=27
\n" ); document.write( "putting in the above formulae
\n" ); document.write( "27=1/2*(2x+3)*(x+3)
\n" ); document.write( "27=1/2*2x^2+6x+9
\n" ); document.write( "27*2=2x^2+6x+9
\n" ); document.write( "54=2x^2+6x+9
\n" ); document.write( "2x^2+6x+9-54=0
\n" ); document.write( "2x^2+6x-45=0
\n" ); document.write( " finding the value of x
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "putting the values in the above equation we get x=3.475,-6.74
\n" ); document.write( "taking the positive value of x
\n" ); document.write( "base=2x+3=2*3.475+3=9.95
\n" ); document.write( "height=x+3=3.475+3=6.475 \n" ); document.write( "

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