document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406884>Question 406884</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mary is 43. Her son is 7. How many years will he be 1/3 Mary's age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286998 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= number of years until Mary's son is 1/3 Mary's age<BR>\n" );
document.write( "So, our equation to solve then is:<BR>\n" );
document.write( "(7+x)/(43+x)=1/3  cross multiply or multiply each side by 3(43+x)<BR>\n" );
document.write( "3(7+x)=43+x<BR>\n" );
document.write( "21+3x=43+x subtract x and also 21 from each side<BR>\n" );
document.write( "21-21+3x-x=43-21+x-x  collect like terms<BR>\n" );
document.write( "2x=22<BR>\n" );
document.write( "x=11 yrs---number of years until Mary's son is 1/3 Mary's age\r<BR>\n" );
document.write( "\n" );
document.write( "CK<BR>\n" );
document.write( "(7+11)/(43+11)=1/3<BR>\n" );
document.write( "18/54=1/3<BR>\n" );
document.write( "1/3=1/3\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps--ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );