document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=406733>Question 406733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parellel tracks. Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h. Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m. At this rate, what time will Train B catch up to Train A?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286990 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parellel tracks. Train A is traveling at a speed of 40 m.p.h and Train B is traveling at a speed of 50 m.p.h. Train A passes the station at 2:25 p.m. and Train B passes the same station at 2:55 p.m. At this rate, what time will Train B catch up to Train A?<BR>\n" );
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document.write( "Train A is 20 miles away when train B passes the station (0.5 hr * 40 mph)<BR>\n" );
document.write( "Train B gains on train A at 10 mph (50 - 40)<BR>\n" );
document.write( "20 mi/10 mph = 2 hours to catch up<BR>\n" );
document.write( "2:55 + 2 = 4:55 PM\r<BR>\n" );
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